Solution to Nishit Sinha

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Incognito
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Hi,

This is Ajit from raipur. I am preparing for CAT 2009 and started with Nishit Sinha. Is there any place where can i find the solutions to the questions given in the book.

Thanks,

timeZtime's picture
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No you wont find it any

No you wont find it any where....but you can search the questions here..if u dont find then post it in question bank.

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Incognito
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2nd edition of Nishit Sinh QA book

hi, i bought 2nd edition Nishit sinha QA book, and it contains solution.

ABHISHEK DUTTA's picture
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Strated a new Thread on Nishit Sinha's problems on DI and LA

Nishit Sinha is really an excellent book and while going through it I personally found out a number of Doubts. I have started a new thread Today at  www.pagalguy.com.

 Here is the link :http://www.pagalguy.com/forum/quantitative-questions-and-answers/37734-cracking-nishit-sinha-problems-quant.html#post1412408

Please feel free to post all your doubts and queries.
 

Incognito
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Thanks for this info

Thanks for this info Abhishek.

Incognito
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can we start somehting

can we start somehting similar here? i dont have a pg id.

Incognito
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soln required

i thought that i can get the solution here !!!! anyways, can somebdoy send a link wehre i can get the solution of nishit sinha book?

Incognito
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Rather starting any new link,

Rather starting any new link, we can share the qs and sols here too.

Ok. here goes my question from chapter 2 numbers:

What is the last digit of LCM of (3^2003 - 1) and (3^2003 + 1)?

Incognito
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4 is the answer and it would

4 is the answer
and it would be zero
for (3^n - 1) and (3^n + 1)where n is even

Incognito
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hi, Can you please explain

hi,
Can you please explain this?
are you taking the units digit and finding the lcm of these two digits?

Incognito
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I also want to have the soln

I also want to have the soln of this q.

As far as i think, only taking the unit digit shld not give the solution....for example unit digit of lcm of 6 and 18 is different than the unit digit of lcm of 16 and 8.
Sorry but dont know how to proceed further...
Smbody plz help

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