ABCD is a square of sidelength 1. A circle is tangent to two sides of
ABCD and passes through exactly one of its vertices. What is the radius of the circle? a. 2 - √ 2 b. 2 + √ 2 c. 2√2 d. None of the above Please solve this with explanation. |
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The diagram shows that r is the length of the hypotenuse OD of an
isosceles right angled triangle whose legs have length 1 - r. Therefore:
r2 = (1 - r)2 + (1 - r)2
=>r = 2- √2.
n/a
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