GEOMETRY- TRIANGLE
Mon, 2007-09-17 10:40
In right angled triangle ABC angle B = 900 where CD and AE are angle bisctors of angles C and A respectively. AE = 9 and CD = 8√2. What is the lenght of AC?
Tue, 2007-09-18 16:58
#3
Here it goes
Let a = height =AB, b = base= BC and h=AC
The AE = 9 = √ [ah { (a + h)2 - b2 }] / (a + h)
8√2 = √ [bh { (b + h)2 - a2 }] / (b + h)
and h = √ (a2 + b2 )
Three variables and three equation. . Any one has time to solve it for me. .
Wed, 2007-09-19 18:39
#5
here let side of the
here let side of the triangle is 2x and 2y which are having <90 then AC^2=4(x^2+y^2) and also 81=4x^2+y^2 and 128=x^2+4y^2 which gives 4(x^2+y^2) = (81+128)x4/5 = 209x4/5 = 19x11x4/5 thus AC = 2(19x11/5)^1/2
Sun, 2007-09-30 08:50
#6
Solution
I realized my approach was wrong and I tried the problem again..
Meanwhile I come across a site where solution is available http://www.qbyte.org/puzzles/p023s.html
The solution is 6xsqrt(5)
Sun, 2007-09-30 09:25
#7
Thanks for the link
but its
Thanks for the link
but its more like a JEE problem than CAT
Any one have solved it ???