quadratic equation
Mani Das knows that sinA and cosA are the roots of the equation ax^2 + bx + c = 0. Thus, a. a^2 + b^2 = 0 b. a^2 - c^2 = 0 c. a^2 + b^2 + 2ac= 0 d. a^2 - b^2 + 2ac = 0 If p and q are the roots of the equation 1/x + 1/(x+a) = 1/(a+b) + 1/b and p + q = 0, then a. a = (+-)(sqrt2)b b. a = (+-)(sqrt3)b c. a = (+-)b/(sqrt2) d. a = (+-)b/(sqrt3)
Mani Das knows that sinA and cosA are the roots of the equation ax^2 + bx + c = 0. Thus,
a. a^2 + b^2 = 0
b. a^2 - c^2 = 0
c. a^2 + b^2 + 2ac= 0
d. a^2 - b^2 + 2ac = 0
Soln. As SinA nd CosA r d roots....
Drfore, SinA + CosA=-b/a....(i)
SinACosA=c/a.........(ii)
As Sin2A + Cos2A =1 =>(SinA +CosA)2 - 2SinACosA=1
Puttin d values we get a^2-b^2+2ac=0
So OPTION (d) Is Correct.....
Giv Ur Best To D World.
Nd D Best Will Cm Back To U.....
Regards,
Dipanjan......
n/a
Mani Das knows that sinA and cosA are the roots of the equation ax^2 + bx + c = 0. Thus,
a. a^2 + b^2 = 0
b. a^2 - c^2 = 0
c. a^2 + b^2 + 2ac= 0
d. a^2 - b^2 + 2ac = 0
Soln. As SinA nd CosA r d roots....
Drfore, SinA + CosA=-b/a....(i)
SinACosA=c/a.........(ii)
As Sin2A + Cos2A =1 =>(SinA +CosA)2 - 2SinACosA=1
Puttin d values we get a^2-b^2+2ac=0
So OPTION (d) Is Correct.....
Giv Ur Best To D World.
Nd D Best Will Cm Back To U.....
Regards,
Dipanjan......
n/a
If p and q are the roots of the equation 1/x + 1/(x+a) = 1/(a+b) + 1/b and p + q = 0, then
a. a = (+-)(sqrt2)b
b. a = (+-)(sqrt3)b
c. a = (+-)b/(sqrt2)
d. a = (+-)b/(sqrt3)
Soln. As 1/x + 1/(x+a) = 1/(a+b) + 1/b
=>x^2(a+2b) + x[a(a+2b) - 2b(a+b)] -ab(a+b)=0[Aftr sm steps]
p + q =-(Coeff of x) nd As p + q = 0
=>2b(a+b)=a(a+2b) =>a^2=2b^2 => a=(+-)Sqrt(2)b
SO OPTION (a) IS CORRECT......
GIV UR BEST TO D WORLD.
ND D BEST WILL CM BACK TO U.....
Regards,
Dipanjan......
n/a
Mani Das knows that sinA and cosA are the roots of the equation ax^2 + bx + c = 0. Thus,
a. a^2 + b^2 = 0
b. a^2 - c^2 = 0
c. a^2 + b^2 + 2ac= 0
d. a^2 - b^2 + 2ac = 0
Soln. As SinA nd CosA r d roots....
Drfore, SinA + CosA=-b/a....(i)
SinACosA=c/a.........(ii)
As Sin2A + Cos2A =1 =>(SinA +CosA)2 - 2SinACosA
Puttin d values we get a^2-b^2+2ac=0
So OPTION (d) Is Correct.....
Giv Ur Best To D World.
Nd D Best Will Cm Back To U.....
Regards,
Dipanjan......
n/a
n/a