There circles are drawn in such a way that each circle is externally tangent to the other two. Each circle is also tangent to two of the sides of an equilateral triangle. If each circle has a radius of 5, what is the perimeter of the triangle? |
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CAT4MBA |
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Any Answer ? ?
One more question
Sorry for the terrible diagram But right now I m in office and the only available SW is word pad.
Angle (EAB) = 30 degree
Angle (ABF) = 90 degree
Angle (BEA) = 60 degree
BE = radius of the circle = 5
=> Tan 30 = 1/√3 = BE/AB
=> AB = 5√3
BC = 10 CD = 5√3
Side of the triangle = 10 ( 1 + √3) And perimeter = 30 ( 1 + √3)
n/a
but my answer comes out to be 10(3)^1/2+30
n/a
One more question
ANS-
Let us assume its an equilateral triangle (option- a), then a=b=c= 1 (say)
Put a=b=c=1 in above eqn n u'll get L.H.S = R.H.S = 3,
Hence t'll be proved that it is an equilateral triangle.
my answer is same as ur ans 10(3)^1/2+30
nishit is correct :
its 3 *10 *(1 + 31/2)
what you guys are doing is 3 *10 *(1 + 1/31/2)
correcting the possible mistake tan 30 = 1/31/2 = 5 / base => base = 5 * 31/2
hopefully you mixed up the perp/ base thing.
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