6 birds, all of a different kind (X1, X2, . ..X6) are put in pairs 3 cages. However, the pairs (X1, X2), (X2, X3). . . .(X5, X6) cannot be put together in a cage. Q1. All the three pairs cannot be determined if it is known that X1 is put together in a cage with Q2. If one of the pairs in a cage is given, then what is the probability that all the other required pairs can be determined? |
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Answers are
Q1. a. X4
Q2 b. 1/2
Please verify it.
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