In a cricket match, average score of any player is given by: Average = Total number of runs scored by the player / Number if times that the player was out Given: A batsman X, played a total of 25 one day matches, he had batted and got out in each of the 25 matches played. It is also known that his score in no two matches was the same. Further, the sum of his top five scores was 337. All the questions that follow are based only on the scores of the above mentioned batsman in the 25 matches played. 1) If the sum of his lowest five scores was 121, his average score was atmost: a)50.04 b)54.28 c)52.52 d)57.12 e)None of these 2) Given that his lowest five scores added up to 121 and his average was more than 40, the number of matches in which he scored less than 40 was at most: a)13 b)12 c)18 d)17 e)15 3) If his lowest five scores added up to 121, his sixth highest score was at least a) 41 b)42 c)44 d)47 e)None of these 4) If it is known that he made two centuries (i.e, a score of 100 or more), his lowest score was at most a) 18 b) 24 c) 27 d)29 e) None of these 5) If it is known that the total number of runs he had made was the maximum possible, which of the following could have been the highest score he made: a) 69 b) 71 c) 75 d) 251 e) More than one of the above
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just check if we take it as 66 then the series with minimum top 5 value ‘ ll be 66 + 67 + 68 + 69 + 70 = 340 which is more than 337.
Given that his lowest five scores added up to 121 and his average was more than 40, the number of matches in which he scored less than 40 was at most:
a)13 b)12 c)18 d)17 e)15
ANS: Sum of lowest score 121
The numbers are : 22 23 24 25 27
Possible numbers less than 40 are : 28 - 39 = 12
Total numbers less than 12 + 5 = 17
Please read the solution of Q1.
My answers are as follows :
1-c
2-c
3-b
4-b
5-d
n/a
But I got the answer 2 as d
hey guys..wats d explanation for ques 4?
Total score to be maximised keeping 2 highest innings 100 or more so
100+101+201
remaining total of three highest score is 337-201= 136
again to have maximum fifth highest score the split can be made as 47,45,44
So the lowest run can be atmost = 44-20=24
Your answer is hereby ratified.
n/a
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