plz solve and explain this question

In a cricket match, average score of any player is given by:

Average = Total number of runs scored by the player / Number if times that the player was out

Given:

A batsman X, played a total of 25 one day matches, he had batted and got out in each of the 25 matches played. It is also known that his score in no two matches was the same. Further, the sum of his top five scores was 337.

All the questions that follow are based only on the scores of the above mentioned batsman in the 25 matches played.

1) If the sum of his lowest five scores was 121, his average score was atmost:

a)50.04

b)54.28

c)52.52

d)57.12

e)None of these

2) Given that his lowest five scores added up to 121 and his average was more than 40, the number of matches in which he scored less than 40 was at most:

a)13

b)12

c)18

d)17

e)15

3) If his lowest five scores added up to 121, his sixth highest score was at least

a) 41

b)42

c)44

d)47

e)None of these

4) If it is known that he made two centuries (i.e, a score of 100 or more), his lowest score was at most

a) 18

b) 24

c) 27

d)29

e) None of these

5) If it is known that the total number of runs he had made was the maximum possible, which of the following could have been the highest score he made:

a) 69

b) 71

c) 75

d) 251

e) More than one of the above

 

My answers are Q1. c .
My answers are Q1. c . 52.52
Q2. d. 17
Q3. b. 42
Q4. b. 24
Q5. b. 71
 
I ll write the solution with my explanation after some time
Q1. Sum of his top 5 scores
Q1. Sum of his top 5 scores = 337
One possible combination 65, 66, 67, 68 and 71.
 
There are many other possible combinations but for q1 where we have to maximize the average, above is the best possible combination
 
why?
 
The value of lowest 5 and highest 5 scores are fixed – 121, 337
 
To maximize the average we should choose the maximum possible values of the rest 15 numbers.
 
Now if we select the highest value anything more than 71 then the lowest value of top ‘ll be less than 64 and which means the maximum possible value of 15 numbers ‘ll be less than 64.
 
Then why shd nt we take the lowest value of top 5 numbers more than 65?
just check if we take it as 66 then the series with minimum top 5 value ‘ ll be 66 + 67 + 68 + 69 + 70 = 340 which is more than 337.
 
Thus the above series is the best possible one to maximize the average.
 
Now the 15th number is 64 and other numbers are 63, 62, . . . . . .50
 
Sum of all the 15 numbers = 15/2 [ 2 x 50 + 14 x 1]
= 15 [ 57]
=  855
 
Total value = 855 + 337 + 121 = 1313
 
And Average = 1313/25 = 52.52
Answer 2

Given that his lowest five scores added up to 121 and his average was more than 40, the number of matches in which he scored less than 40 was at most:

a)13        b)12          c)18          d)17         e)15

ANS: Sum of lowest score 121

The numbers are : 22      23      24       25     27

Possible numbers less than 40 are : 28 - 39 = 12

Total numbers less than 12 + 5 = 17

Last five numbers 22, 23,
Last five numbers 22, 23, 24, 25 , 27
And the next 15 numbers are 28, 29, 30, . . . . . .
 
Sixth highest score = 20 th number from the lowest or 15th from 28
i. e 28 + 14 = 42
Answer Q5

Please read the solution of Q1.

My answers are as follows

My answers are as follows :

1-c

2-c

3-b

4-b

5-d

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Am I wrong

But I got the answer 2 as d

hey guys..explanation for

hey guys..wats d explanation for ques 4?

Solution to Q4

Total score to be maximised keeping 2 highest innings 100 or more so

100+101+201

remaining total of three highest score is 337-201= 136

again to have maximum fifth highest score the split can be made as 47,45,44

So the lowest run can be atmost = 44-20=24

Solution to Q4

Your answer is hereby ratified.

 

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