A, B, C, D and E are five taps. Capacity of B is 2 times of A, capacity of C is 3 times that of A. Capacities of D and E are 4 and 5 times that of A respectively. In the first case A, C and E act as input pipes and B and D act as output pipes. In the second case C, D , E act as input pipe and A and B act as output pipes. If A and D working together as input pipes can fill the tank in 4 hours, then what is the difference in time required to fill the tank in the first and second case stated above? |
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Answer b. 3.33 hrs.
Thats right the answer is b. 3.33 hour
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