Solve it in the shortest possible way..

Q1) Which of the following is the smallest?
a)5^(1/2)  b)6^(1/3)    c) 8^(1/4)   d) 12^(1/4)

Q2) When x is divided by 6 the remainder is 3.What will be the remainder when (x^4+x^3+x^2+x+1) is divided by 6?
a)3    b)  4   c) 1   d)5

Q3)1010101....94 times.What will the remainder when it will be divided by 375.
a)320  b)10   c) 40  d) None of these.

Q4)Sita added first N natural number and got the solution 1850.She soon realised that she had added one number twice.Find the differnce between N and that number.
a)40  b)33   c)60   d)17

Q5)When I distribute N number of chocholates (N is in between 1000 and 2000) among 7 students,4 chocholates are left with me.If i distribute the same number of chocholates among 11 students I am left with 6 chocholates.How many chocholates will I be left with when I will distribute it among 13 students?
a)2   b)3    c)6   d) 7

‹ querry Geometry II ›

Submitted by shivanibusiness on Thu, 2008-05-15 11:41.

commented on:  Thu, 2008-05-15 12:32

CAT@IIMs's picture

CAT@IIMs points: 259
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Q1) Which of the following is the smallest?

Soln.:
         Let P=5^1/2 =>P^12=5^6=125^3...(i)
              Q=6^1/3 =>Q^12=6^4...(ii)
              R=8^1/4=>R^12=8^3..(iii)
              S=12^1/4=>S^12=12^3...(iv)
So its easy to determine dt among P,R,S R is smallest
As,R^12=512 & Q^12=1296
So,R is smallest no.

Option (c) is correct....

Giv ur best to d world.
Nd d best will cm back to u....

Regards,
Dipanjan......

commented on:  Thu, 2008-05-15 12:42

CAT@IIMs's picture

CAT@IIMs points: 259
Location:
Comments : 117


Q2) When x is divided by 6 the remainder is 3

Soln.:f(6)=3 or f(6)=-3
by takin ny one u can solve d problem..
As, 3^4+3^3+3^2+3+1=121=1(mod 6)

So option (c) is correct...

Giv ur best to d world.
Nd d best will cm back to u....

Regards,
Dipanjan.....

commented on:  Thu, 2008-05-15 12:59

CAT@IIMs's picture

CAT@IIMs points: 259
Location:
Comments : 117


Q3)1010101....94 times.What will the remainder

Soln.:As,1010...90 times is divisible by 3
        1010..94 times=1010.......0000+1010
                              90 times          
        First part is fully divisible by 375[As, 375=125*3]
        1010=260(mod 375)
So option (d) is correct.....

Giv ur best to d world.
Nd d best wil cm back to u....

Regards,
Dipanjan......

commented on:  Thu, 2008-05-15 13:18

CAT@IIMs's picture

CAT@IIMs points: 259
Location:
Comments : 117


Q4)Sita added first N natural number

Soln.:
         Suppose d original is X, & Sita added Y twice.
         Drfore,N(N+1)*2=X
         As Sita added a Y twice dn we can say dt:
         So,X=1850-Y...
         D nearest value of X is 1830[Put N=60,Dn 60*61/2=1830]         
         =>Y=20
Drfore,N-Y=60-20=40..

So OPTION (a) is corect....

Giv ur best to d world.
Nd d best will cm back to u....

Regards,
Dipanjan......
 

commented on:  Thu, 2008-05-15 13:29

CAT@IIMs's picture

CAT@IIMs points: 259
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Comments : 117


@Shivani

I thnk dt qs has an error....
In d first time dr is no mention abt d no. of studends among whom the chocholates are distributed....
Plzz correct dt or let me allow to knw whether d qs is actually correct?

Giv ur best to d world.
Nd d best will come back to u.....

Regards,
Dipanjan.....

commented on:  Thu, 2008-05-15 13:38

shivanibusiness's picture

shivanibusiness points: 537
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Comments : 203


Hi Dipanjan, Thanks for

Hi Dipanjan,

Thanks for correcting me..yup I just missed to mention the number of students ...its 7.

"To get the BEST, be the BEST"

commented on:  Thu, 2008-05-15 22:27

Incognito's picture

Incognito (not verified) points: 0
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Comments : 1100


dont got it yaar

dont got it yaar