i need help on this question.

Q) M is the number of sets containing odd number of consecutive positive integers whose sum is 2002. n is the number of sets containing even number of consecutive positive integers whose sum is 2002. then

  • a. m > n> 3
  • b. m = n = 3
  • c. m = n = 4
  • d. None of these
  • e.Not Attempted

Reply

Hi friends I am giving a reply after a lot of days..Here also I can say wdout CAT4MBA mates  I may not able to post the soln. of it.

Soln.:
For odd m:
283+284+285+286+287+288+289=2002
For even n:
499+500+501+502=2002

So m>n>3
Option (a) is correct.
[N.B.:just have a look on the unit digit.Try all possibilites to get 2 from 0+1+2+...+9.Anyway good problem]

Giv ur best to d world.
Nd d best will cm back to u....

Regards,
Dipanjan.....

__________________

n/a

bit confused with tht!!!

im sorry but....i think wht they have asked in the qn is the number of sets, and not number of element....so by showing tht example isnt it an inappropriate soln....or is it tht the qn is incorrectly put???

thanx for ur reply.....i guess i need more help....

sab

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