TELL ME SOMETHING ABT NIILM - DELHI..........HOW'S THE COLLG ........I HAVE RECEIVE A CALL LETTER BY DAT INSTI FOR GD ND PI...........I DIDN'T APPLIED EVER FOR THE SAME ........BUT THEY R INVITING ME..........KINDLY TELL ME .......IS IT WORTH.
Bt ths procees can calculate the total no. of zeros in n!.I thnk by this process we cant calculate the no. of zeros at the end of 36!.......Plz look closely on d qs.........What do u thnk is it sufficient to cal d no. of zeros at d end of 36!^36!...
If u thnk dt process is correct thn plz explain it..............
So Number of zeros at the end of 36! 36! = 8 36!
n/a
I know urs way, bt my qs is how can u decide dt that process gives the no. of zeros at the end, nt overall.....
Watin 4 re......
Thank you,
Dipanjan
n/a
HEY ALL,
TELL ME SOMETHING ABT NIILM - DELHI..........HOW'S THE COLLG ........I HAVE RECEIVE A CALL LETTER BY DAT INSTI FOR GD ND PI...........I DIDN'T APPLIED EVER FOR THE SAME ........BUT THEY R INVITING ME..........KINDLY TELL ME .......IS IT WORTH.
My qs is
No. of zeros in n!=[n/5]+[n/5^2]+......
Bt ths procees can calculate the total no. of zeros in n!.I thnk by this process we cant calculate the no. of zeros at the end of 36!.......Plz look closely on d qs.........What do u thnk is it sufficient to cal d no. of zeros at d end of 36!^36!...
If u thnk dt process is correct thn plz explain it..............
Thank You.
Dipanjan
its 36!*8
(100)^3 has 6 zeros
i.e num of 0's in the base *the power
36! has 8 zeros..
so (36!)^36! has...8*36! zeross....
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