Number System
Find the number of zeros at the end of 36!^36!............
Regards,
Dipanjan
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I know urs way, bt my qs is how can u decide dt that process gives the no. of zeros at the end, nt overall.....
Watin 4 re......
Thank you,
Dipanjan
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HEY ALL,
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My qs is
No. of zeros in n!=[n/5]+[n/5^2]+......
Bt ths procees can calculate the total no. of zeros in n!.I thnk by this process we cant calculate the no. of zeros at the end of 36!.......Plz look closely on d qs.........What do u thnk is it sufficient to cal d no. of zeros at d end of 36!^36!...
If u thnk dt process is correct thn plz explain it..............
Thank You.
Dipanjan
its 36!*8
(100)^3 has 6 zeros
i.e num of 0's in the base *the power
36! has 8 zeros..
so (36!)^36! has...8*36! zeross....
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So Number of zeros at the end of 36! 36! = 8 36!
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