Q1)Mr Sharma starts from his house to office 3o mins late then his usual time.So, he increases his speed by 25% over his usual speed but still reaches 15 mins late. Another day he starts 15 mins later then his usual time and increases his speed by 505 comparatively to the previous day speed and reaches 20 mins before the office time.What is the distance between Mr.Sharma house and office? A) 10Km B)15 Km C)5 Km D)20Km E)25 Km Q2) How Many factors does N=23×32×54 have that ends with zero? A)60 B)24 C)36 D)48
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Q2) How Many factors does N=23×32×54 have that ends with zero?
A)60 B)24 C)36 D)48
Sol.
3 x 3 x 4 = 36
Q1)Mr Sharma starts from his house to office 3o mins late then his usual time.So, he increases his speed by 25% over his usual speed but still reaches 15 mins late. Another day he starts 15 mins later then his usual time and increases his speed by 505 comparatively to the previous day speed and reaches 20 mins before the office time.What is the distance between Mr.Sharma house and office?
A) 10Km B)15 Km C)5 Km D)20Km E)25 Km
@ Jyoti
plz check problem...................
Here N = 2^3x3^2x5^4 Let P=N/10 = 2^2x3^2x5^3 There total factors of P is (1+2)x(1+2)x(1+3) = 3x3x4=36.
Q1)Mr Sharma starts from his house to office 3o mins late then his usual time.So, he increases his speed by 25% over his usual speed but still reaches 15 mins late. Another day he starts 15 mins later then his usual time and increases his speed by 50% comparatively to the previous day speed and reaches 20 mins before the office time.What is the distance between Mr.Sharma house and office?
A) 10Km B)15 Km C)5 Km D)20Km E)25 Km
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