permutations

Cud any1 please explain me how to solve this
how  many 6 diigit numbers are possible with exactly 4 different digits

Consider this as 6 places to

Consider this as 6 places to be filled up with 4 different digits out of available 10 different digits

---- ----- ---- ----- ----- -----

First Place can be filled up with 9 different digit.
Second Place can be filled up with 9 different digit.
Third Place can be filled up with 8 different digit.
Fourth Place can be filled up with 7 different digit.
5th and 6th place can be filled up with 4 different digits each.

Total possible numbers = 9 * 9 * 8 * 7 * 4 * 4 = 72576

no its wrong

no its wrong

hi abhijith can utell

hi abhijith

can utell me    ans is 408240

if correct then i explain u, and if  wrong then try    to find ansfor secondtime plz reply me

Little Star 

__________________

n/a

It should be C (10, 4) x 4^6

It should be C (10, 4) x 4^6 - 4^5

It should be C (10, 4) x 4^6

It should be C (10, 4) x 4^6 - 4^5

ans is 294840 its ther e in

ans is 294840 its ther e in arun sharma refer to q 30 level 3 ,i dont know how he gt that

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