There are ‘m’ points on one straight line AB and ‘n’ points on another straight line AC, none of them being A. How many triangles can be formed with these points as vertices? How many can be formed if point A is also included?
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CAT4MBA |
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hey der ans is simple
for triangle u need 3 points but for that u have to select 2 pints from 1 line and another 1 point from anoter line
so
for case (1) u select 2 points from AB line and 1 point from AC line
or 2 points from AC line and 1 point from AB line
so ans is mC2 * nC1+mC1*nC2
for second case
u have 1 more point A
so m+1c2 x nC1 but here u cant take n+1c2 x mC1 because A point already taken in m+1C2
so ans is m+1C2*nC1+mC1*nC2
so final ans option(3)
LIttle Star
n/a
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