plaease help....MATH KILLIN ME
PLEASE GIVE EXPLANATIONS ALSO
Q1)if a+b+c =20 and 1/a+1/b+1/c=30, then the value a/b+b/c+a/c+c/a+b/c+c/b is
a.597 b.8 c.350 d.441
Q2)a,b,c,d are real no.s and a2 + b2+ c2+ d2=100 then ahat is the max value of 2a + 3b + 6c + 24d
a.240 b.250 c.300 d.360
Q3) x13+x+90 is divided by x2 - x + n,remainder obtained is zero . how many integral values of n is /are possible
a.0 b.1 c.2 d.infinite
Q4)How many diff length diagonals are possibleof convex regular decagon
a.35 b. 2.7 c.27 d.5 e.4
Q5)x+y+z=6, x2 + y2 + z2=8, x3 + y3 + z3 = 5 what is the value of x4+y4+z4 equal to
a.0 b.1 c. 9 d.cannot be determined
Q6) if x , y , n are all positive integers.for how many possible values of a,b and is xn-yn = 2100?
a.50 b.100 c.1 d.none of these
s shahid basha
Q2.
Since the coefficient of 'd' is 24.
the max value which 'd' can have is 10 ( according to the given equ)
so the max value is 240.
But i'm not sure. Check with others.
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shabash_23 is correct.
as a, b, c , d are not given as not same or not equal to zero the max value is for all zero and d =10
and thats 240
Another question : What is the minimum value of 2a + 3b + 6c + 24d ?
My ans:
I think here a = b= c = d =5
and the value = 35 x 5 = 175
The minimum value of 2a + 3b + 6c + 24d should be when 'a' is equal to 10.
i.e the minimum value is '20'.
thank u
shahid.
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Q4)How many diff length diagonals are possibleof convex regular decagon
a.35 b. 2.7 c.27 d.5 e.4
ANS:
10C2 (Total possible lines) - 10 (sides) = Number of diagonals = 35
The question asked is number of different lengths of diagonals in a convex regular decagon.
The answer '35' u gave is number of diagonals. All diagonals are not of equal lengths.
Anyways thanks for trying.
shahid.
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Here Q asks for "diff length diagonals " not total # of diagonals. Also, note that - it is convex regular decagon
So, my take is - from each point you can draw - 8 diagonal - within there are 4 pairs each having same lengths.
So, answer is - e.4
@angs
thanks for ur reply. But in a converx regular decagon one can draw only '7' diagonals (not 8) from one
corner.
shahid
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u r correct shahid - sorry 4 the mistake - but anyway, answer remains same - out of 7 - except middle one - others forms 3 pairs each having 2 same length diagonals. Hence - e.4
s shahid basha
Q1
the question should be like this
a/b+b/c+a/c+c/a+b/a+c/b.
the solution is as follows :
(a+b+c)(1/a+1/b+1/c) = 20 X 30
a/b+b/c+a/c+c/a+b/a+c/b = 597.
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