Please give some easy solutions to following CL Questions
Q1. P is a set containing all natural numbers less than 200, which can be expressed as the product of a ‘perfect square’ and a ’perfect cube’. If any element is chosen at random from ‘P’, then what is the probability that it will have exactly 12 factors? b. 1//1
c. 1/7
d. 1/10
Q2. If the system of equations (2x + 5y + 3z = 4, 4x + 3y = -1 and 2y + 5z = 19 have a unique solution, then find the value of ( x + y + z) [x, y and z are real numbers] a. 3
b. 4
c. 6
d. 10
Q3. If the difference between two numbers ‘PQR’ and ‘RQP’ is ‘PP’ in base 6, then what is the value of ‘P + Q + R’ in base 6? [P, Q and R are distinct single digit numbers ] a. 10 b. 11
c. 12
d. Cannot be determined
Q4. How many integral solution exist for the equation 5x – y – 120 =0, such that the values that ‘x’ assumes have opposite sign as compared to corresponding values of y? b. 23
c. 24
d. 25 |
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Q1. P is a set containing all natural numbers less than 200, which can be expressed as the product of a ‘perfect square’ and a ’perfect cube’. If any element is chosen at random from ‘P’, then what is the probability that it will have exactly 12 factors?
a. 2/21
d. 1/10
Ans. 2/21
Q1. P is a set containing all natural numbers less than 200, which can be expressed as the product of a ‘perfect square’ and a ’perfect cube’. If any element is chosen at random from ‘P’, then what is the probability that it will have exactly 12 factors?
a. 2/21
d. 1/10
Ans. 2/21
Q4. How many integral solution exist for the equation 5x – y – 120 =0, such that the values that ‘x’ assumes have opposite sign as compared to corresponding values of y?
a. 22
d. 25
Ans. 23
Q2. If the system of equations (2x + 5y + 3z = 4, 4x + 3y = -1 and 2y + 5z = 19 have a unique solution, then find the value of ( x + y + z) [x, y and z are real numbers]
d. 10
Ans. 4
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