Ratio and Proportion – Original CAT questions 1
CAT questions from CAT 1999 onwards are available on the site so I wont write those questions again here. Following are the real CAT questions asked before year 1999
Q1. I have one rupee coins, fifty paise coins and twenty five paise coins. The number of coins are in the ratio 2.5 : 3 : 4. If the total amount with me is Rs. 210, find the number of one rupee coins. (CAT 98)
a. 90 b. 85 c. 100 d. 105
Q2. A student gets an aggregate of 60% marks in five subjects in the ratio 10 : 9 : 8 : 7 : 6. If the passing marks are 50% of the maximum marks and each subject has the same maximum marks, in how many subjects did he pass the examination ? (CAT 97)
a. 2 b. 3 c. 4 d. 5
Q3. A dealer buys dry fruits at Rs. 100, Rs. 80 and Rs. 60 per kilogram. He mixes them in the ratio 3 : 4 : 5 by weight. And sells at a profit of 50%. At what price per kilogram does he sell the dry fruit? (CAT 97)
a. Rs. 80 b. Rs. 100 c. Rs. 95 d. None of these
Q4. The cost of diamond varies directly as the square of its weight. Once, this diamond broke into four pieces with weights in the ratio 1 : 2 : 3: 4. when the pieces were sold, the merchant got Rs. 70,000 less. Find the original price of the diamond? (CAT 96)
a. 1.4lakh b. Rs. 2 lakh c. Rs. 1 lakh d. Rs. 2.1 lakh
Q5. Two liquids A and B are in the ratio 5 : 1in container 1 and 1 : 3 in container 2. In what ratio should the contents of the two containers be mixed so as to obtain a mixture of A and B in the ratio 1 : 1? (CAT 96)
a. 2 : 3 b. 4 : 3 c. 3 : 2 d. 3 : 4
Q2. A student gets an aggregate of 60% marks in five subjects in the ratio 10 : 9 : 8 : 7 : 6. If the passing marks are 50% of the maximum marks and each subject has the same maximum marks, in how many subjects did he pass the examination ? (CAT 97)
a. 2 b. 3 c. 4 d. 5
Soln. Take d max mark in each subject is 100. So qualifying mark is 50. On a total dt fellow gets 60 x 5= 100.
We can write (10+9+8+7+6)a=300 => a=15/2
In 5 subjects he gets 75,67.5,60,52.5,45.
He passes in 4 subjects...
So option (c) is correct......
Giv ur best to d world.
Nd d best will cm back to u...
Regards,
Dipanjan.....
n/a
Q4. The cost of diamond varies directly as the square of its weight. Once, this diamond broke into four pieces with weights in the ratio 1 : 2 : 3: 4. when the pieces were sold, the merchant got Rs. 70,000 less. Find the original price of the diamond? (CAT 96)
a. 1.4lakh b. Rs. 2 lakh c. Rs. 1 lakh d. Rs. 2.1 lakh
Soln. As C=kW2[K is proportionality constant]
So, 100kW2 - (1+4+9+16)kW2 = 70000
=>kW2 = 1000
Price of dt diamond = 1000 x 100 = 1lakh.
OPTION (c) is correct......
Giv ur best to d world.
Nd d best will cm back to u....
Regards,
Dipanjan......
n/a
Q3. A dealer buys dry fruits at Rs. 100, Rs. 80 and Rs. 60 per kilogram. He mixes them in the ratio 3 : 4 : 5 by weight. And sells at a profit of 50%. At what price per kilogram does he sell the dry fruit? (CAT 97)
a. Rs. 80 b. Rs. 100 c. Rs. 95 d. None of these
Soln. Total cost to buy Rs(300 + 320 + 300)=Rs 920.
Total cost to cell Rs (920 + 410)=Rs 1330.
As he bought 12 kg of dry fruits. Sellin cost per kg. is Rs. (1330/12)=Rs. 111(Approx)
SO OPTION (d) is correct.
Giv ur best to d world.
Nd d best will cm back to u....
Regards,
Dipanjan.......
n/a
answer to Q5 is
d . 3 : 4
If and Only if the volume of both the containers are same.
but thats not mentioned in the questions
n/a
Q3. A dealer buys dry fruits at Rs. 100, Rs. 80 and Rs. 60 per kilogram. He mixes them in the ratio 3 : 4 : 5 by weight. And sells at a profit of 50%
. At what price
kilogram does he sell the dry fruit? (CAT 97)
a. Rs. 80 b. Rs. 100 c. Rs. 95 d. None of these
Soln. Total cost to buy Rs(300 + 320 + 300)=Rs 920.
Total cost to cell Rs (920 + 460)=Rs 1380.
1380/12=115 ans is (d) none of these.
Udit Garodia
dude something is wrong with your multiplication ans is c ie 105
Q1. I have one rupee coins, fifty paise coins and twenty five paise coins. The number of coins are in the ratio 2.5 : 3 : 4. If the total amount with me is Rs. 210, find the number of one rupee coins. (CAT 98)
a. 90 b. 85 c. 100 d. 105
Soln. As d no. ratio of 1 rupee, 50 paise, 25 paise in 2.5:3:4
=>In value it wud be 2.5:(3/2):(4/4) = 2.5:1.5:1....
No. of 1rupee coins 2.5 x (210/5)=110....
OPTION (d) is correct......
Giv ur best to d world.
Nd d best will cm back to u.....
Regards,
Dipanjan.....
n/a
n/a