35 tough questions on reminder

Q1. The unit digit of 23 4 x 34 5 x 45 6 x 67 8 x 78 9 is

Q2. If 2 n can exactly divide p! then the value of n which is not possible :
a. 43              b. 44                  c. 45              d. None of these

 Find  the reminders when

Q3. 6 6 6 . . . . . . Infinity is divided by 10.

Q4. 888222888222. . . . . up to 9235 digits divided by 53

Q5. 1 x 2 + 3 x 4 + 5 x 6 +  7 x 8 + . . . 10 terms divided by 19

Q6.  11 3 + 9 3 is divided by 7 3

Q7. 4 4 n + 3 is divided by 7
a. 0               b. 1                  c. 5                    d. None of these

Q8. 3 0 + 3 1 + 3 2 + . . . . .201 terms is divided by 13
a. 0              b. 12                  c. 3                   d. None of these

Q9. 1 3 + 2 3 + 3 3 +           1000 3 is divide by 13

Q10. 10 2 + 11 2 + 12 2 +  . . . .  28 2 is divided by 19

Q11.  21 12 – 12 21 is divided by 7

Q12. 23 32 – 9 is divided by 16

Q13. 1 3 + 2 3 + 3 3 + 4 3 +. . 10 terms is divided by 1 2 + 2 2 + 3 2 + 4 2 + . . .10 terms

Q14. 3 37 + 4 37 is divided by 7

Q15. 10 3 + 9 3 is divided by 12 3?

Q16. 10 11 12 is divided by 13

Q17.  999 9  is divided by 99 9

Q18. 999 9  is divided by 99 9 an then by 9 9

Q19. 12121212. . .  300 times is divided by 99

Q20.  12233344455555…100 terms divided by  7

Q21.   (10 3 + 9 3)752 is divided 12 12

Q22.  44444 + 3333 is divided by 7

Q23. 1! + 2! + 3! +  . . . .70! divided by 100

Q24.  3456 is divided by 108?

Q25. 1 1 + 2 2 + 3 3 + . . . .100 100 is divided by 4?

Q26. 3 3 3 3 3 3 3 3 3. . .1001 digits. . . . divided by 1001

Q27. 4 + 44 + 444 +. . .100 terms. . divided by  7

Q28. 4 44 is divided by 15.

Q29.  37! 37! Divided by 100

Q30.  17 x 18 x 19 x . . . .  37     divided by 100

Q31.  4 101 is divided by  5

Q32.  1 3 + 2 3 +  3 3 + . . . . .99 3  is divided by 10

Q33. 2222 5555 + 5555 2222 is divided by 7

Q34. Find the sum of all two-digit numbers that give a reminder 4 when they are divided by 5
a. 98,270                  b. 99,270                  c. 1,02, 090

Q35. When 7179 and 9699 are divided by another natural number N, remainder obtained is same. How many values of N will be ending with one or more than zeroes?
a. 24               b. 124                   c. 46                       d. None of these   

i4iim's picture
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few answers

Thz a huge collection. . answers of few easier ones

Q6. 2

Q11. I think it shd be 12 21 - 21 12 . . answer 6

Q12. ans 8

'll post the other answers soon

jigar_er_civil's picture
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ans

Q28. 4 44 is divided by 15.

ans(4^2)^22 =16^22 so reminder=1

 

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nishit's picture
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Q3 answers

Divided by 10 means finding the last digit

6 to the power anything ‘ll always end with 6 so the reminder is 6.
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nishit's picture
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Q5 answer

1 x 2 + 3 x 4 + 5 x 6 +  7 x 8 + . . . 10 terms divided by 19

 
∑ n (n + 1)     
 
= ∑ n2  + ∑ n
 
= 1/6 n (n+1) (2n +1) + n(n+1)/2      where n = 10
 
=  1/6 x 10 x 11 x 24 = 40 x 11 = 440
 

440 = 3 (mod 19)

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jigar_er_civil's picture
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ans

Q33. 2222 5555 + 5555 2222 is divided by 7

2222 divided by 7 reminder =3

5555 divided by 7 reminder=4

now (4^2)1111 + (3^5)1111 so 16+243=259 divided by 7so reminder =0

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jigar_er_civil's picture
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ans

Q31.  4 101 is divided by  5

(4^2)^50 x 4 divided by 5 reminder=1*4=4

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jigar_er_civil's picture
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ans

Q6.  11 3 + 9 3 is divided by 7 3

ans 2

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jigar_er_civil's picture
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Q14. 3 37 + 4 37 is divided

Q14. 3 37 + 4 37 is divided by 7

ans a^n + b^n divided by a+b when n is odd

so reminder=0

 

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jigar_er_civil's picture
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ans

Q32.  1 3 + 2 3 +  3 3 + . . . . .99 3  is divided by 10

sum of cube=(n(n+1)/2)^2=99*99*100*100/4 divided by 10 so reminder= 0

 

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Thanks Nishit /

Thanks nishit / jigar_er_civil for the asnwers

Still on line!! not watching the match

 

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