1! + 2! + 3! + ......................................999! is divided by 1120, what is the remainder?
1120 = 2 x 56 x 10
= 2 x 28 x 2 x 10
= 25 x 7 x 5
So any number with above prime factors 'll be divisible by 1120.
and the mimum factorial with above factors = 8!
i.e all the numbers after 8! 'll be divisible by 1120.
Thus
reminder of 1! + 2! + 3! + ......................................999! is divided by 1120 =
reminder of 1! + 2! + 3! + ...7! is divided by 1120
and thats 313
n/a
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1120 = 2 x 56 x 10
= 2 x 28 x 2 x 10
= 25 x 7 x 5
So any number with above prime factors 'll be divisible by 1120.
and the mimum factorial with above factors = 8!
i.e all the numbers after 8! 'll be divisible by 1120.
Thus
reminder of 1! + 2! + 3! + ......................................999! is divided by 1120 =
reminder of 1! + 2! + 3! + ...7! is divided by 1120
and thats 313
n/a
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