Remainder Questions:
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Please post the solution along with answer. TIA
Q1) Remainder of 32^32^32 divided by 7?
a) 2 b) 3 c) 4 d) 6
Q2) Remainder of (22^33+10^35) divided by 45?
a) 2 b) 11 c) 8 d) None of these
Q3) Remainder of (1^1+2^2+3^3+....+10^100) divided by 4?
a) 0 b) 1 c) 2 d) 3
Q4) Remainder of 3^450 divided by 108?
a) 3 b) 1 c) 27 d) 81
Q5) Remainder when (1!+2!+3!+.....1000!) divided by 5?
a) 1 b) 2 c) 3 d) 4
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Q4) Remainder of 3^450 divided by 108?
a) 3 b) 1 c) 27 d) 81
here 108=3*3*3*4=27*4
so finally we get 3^447 divided by 4
now 3^447 written as 9^223*3 divided by 4 so remider=1*3 =3
Little Star
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Q3) Remainder of (1^1+2^2+3^3+....+10^100) divided by 4?
a) 0 b) 1 c) 2 d) 3
can u clear, here in last term 10^10 or 10^100(this one not possible) or 100^100
plz correct it
Little Star
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Q3) Remainder of (1^1+2^2+3^3+....+10^100) divided by 4?
a) 0 b) 1 c) 2 d) 3
ans is 0
Little Star
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Q1) Remainder of 32^32^32 divided by 7?
a) 2 b) 3 c) 4 d) 6
ans is 4
Little Star
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your answer is wrong
32*32*32/7
4*4*4/7
64/7
1 remainder
Arpitbhai
here u r for CAT not for 2nd standard school exam
so data is 32^32^32 not 32*32*32
Little Star
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Q4) Remainder of 3^450 divided by 108?
ur answer is wrong..
i tried using various methods...
the right answer is 81.......
all even nums are div. by 4 so lets consider only odd nums..
1^1 rem =1
3^3 rem =(-1)^3=-1
5^5 remdr = 1
7^7 rem = -1
9^9 rem= 1
addin we get rem upto 10^10= 1
rem upto 100^100=1*10= 10 i.e. rem =2 
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Q5) Remainder when (1!+2!+3!+.....1000!) divided by 5?
a) 1 b) 2 c) 3 d) 4
here from 5! to 1000! divided by 5
so we have to find just 1!+2!+3!+4!=33 so reminder=3
Little Star
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