Remnder Nishit sinha
Please solve the qs 31 of number system
N is a number which
when divided by 10 gives 9 as the reminder
when divided by 9 gives 8 as the reminder
when divided by 8 gives 7 as the reminder
when divided by 7 gives 6 as the reminder
when divided by 6 gives 5 as the reminder
when divided by 5 gives 4 as the reminder
when divided by 4 gives 3 as the reminder
when divided by 3 gives 2 as the reminder
when divided by 2 gives 1 as the reminder
when divided by 10 gives 9 as the reminder
what is N?
a. 2519 b. 841 c. 839 d. 2521
This kind of problms is vry easy to solve....
If u see the diff between remainder and divisor remains same for all cases.Then apply ths formula
(L.C.M of divisors) - diff between remainder & divisor
Accordin to ds method N = (L.C.M of 2,3,4...10) - 1
= 2520 - 1 = 2519
So option (a) is correct one.....
Now tell me whether im correct or nt....
GIVE YOUR BEST TO THE WORLD
AND THE BEST WILL COME BACK TO YOU.
Regards,
Dipanjan....
n/a
n/a
see the LCM 2520 is divisible by all the numbers form 2 to 10.
Now stop here.Just think what will be the previous number divisible by 10 it will be 2510.So add the remainder (i.e 9 ) to this you will get 2519.Project and check this for other numbers.Happy math!!
U dont need to add...You hv just to subtract the diff betwn the divisor & remainder from the dividend.........
Try it by takin very easy eg...Its very easy to grab the concept behind it...
Giv Ur Best To The World
And The Best Will Come Back To You..
Regards,
Dipanjan.......
n/a
Sorry Mr Naren I hv misinterprated it.......
Regards,
Dipanjan........
n/a
I think here if we use a bit of elimination process the answer resolves easily.
Just 2 steps.
1. when divided by 10 gives 9 as the reminder
so our options narrowes down to option 1:2519 and option3:839
now
2. Just check either of them which satisfies the next case
when divided by 9 gives as the remainder ,which in case 839 option 3 voids
thus narrowing down the option 1:2519.
of course we can solve this problem by various ways ..................just my opine ........................................DrEaMcAtChEr
This kind of problms is vry easy to solve....
If u see the diff between remainder and divisor remains same for all cases.Then apply ths formula
(L.C.M of divisors) - diff between remainder & divisor
Accordin to ds method N = (L.C.M of 2,3,4...10) - 1
= 2520 - 1 = 2519
So option (a) is correct one.....
Now tell me whether im correct or nt....
GIVE YOUR BEST TO THE WORLD
AND THE BEST WILL COME BACK TO YOU.
Regards,
Dipanjan....
n/a
n/a