Time Questions

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Incognito
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I am expecting some good solutions for the following questions

Each face of a cube is coloured with exactly one colour from among Red, Blue and Green.

Q1. In how many ways can all the faces of the cube be coloured such that exactly two faces are coloured blue?

a. 16                                  b. 10                              c. 15                                    d. None of these

Q2. In how many ways can the all the faces of the cube be coloured such that the number of faces painted blue is either 2 or 3?
a. 10                                 b. 24                              c. 26                                     d. None of these

Q3. 2100! = (504)p x Q, and Q is not  a multiple of 7, what is the value of P?
a. 4                                   b. 348                              c. 522                                          d. 698

imhimanshujaggi's picture
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Q 3

soln 2  q3...

is da ansr a i.e 4...

 

how i calculatd dat..

1.i ve used d same funda...like finding 2 n 5 in 120 !....how v find dat by keep on dividing dat...120/5=20; thn 20/5= 4...so total no f 5 s r= 24 in 120 !

2. by looking at options...other looks vague..!

correct me if um wrong

 

 

nishit's picture
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Answer:  if we represent
Answer:  if we represent 2100! in product of prime factors then it ‘ll contain 3 , 7(for 21 ) and 2,5(for 10)
The question specifies that 2100! = (504)p x Q and Q is not a multiple of 7.
So all the factors of 7 are in (504)p
Now 504 = 7 x 72
Thus its like calculating number of 7’s in 2100! (i. e. 348 is the answer)
 
If the question is changed to something like
2100! = (3528)p x Q, and Q is not  a multiple of 7, what is the value of P?
Then the answer would have been 348/2 = 174

 

If you don’t know how I got the number 348.  It’s simple [2100/7] + [2100/49] + . . . . .

But please don’t do the exact calculation – its time consuming
You should calculate like 2100/7 = 300; 300/7 = 42 ; 42/7 = 6 and the sum = 348
 

In the question there is no 5th option (e) Non of the above
If that had been one of the option then you got to check if enough values of 2 and 3 are there in 2100! To make (504)348
 
Here in 2100! , number of 3’s = 700 + 233 + 77 + 25 + 8 + 2 = 1045
And 2’s = 1050 + 525 + 262 + 131 + 60 + 30 + 15 + 7 + 3 + 1 = 2084
And 504 = 7 x 32 x 23
So we need 2 x 348 number of 3’s and 3 x 348 number of 2’s.

And in 2100! We have enough so there is no problem.

 

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imhimanshujaggi's picture
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re to Q 1

ansr 2 q 1 z  b (10)

 

how i solvd dat...

faces left = 4

3*1+2*2+1*3=10(means 3 faces painted with red n 1 with green n + 2 with red n 2 with green + 3 with green n 1 with red)

thnx

Incognito (not verified)
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Thanks nishit for the great

Thanks nishit for the great explanation . . .time solutions are such horrible . . .

answer for the first and second qs are 16 and 26

abhrabumba's picture
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Excellent explanation.

Yes Nishit. I too beleive your explanation and approach is correct.

 

The future belongs to those who beleive in the beauty of their dreams. Kudos to your effort.

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abhrabumba's picture
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Will it be like this??

For 2 faces of the cube to be painted blue, we consider the following scenarios:

faces left = 4

3*1+2*2+1*3=10(means 3 faces painted with red n 1 with green n + 2 with red n 2 with green + 3 with green n 1 with red)

thnx

For the 3 faces of the cube to be painted blue:

faces left = 3

So the cases are (2 G and 1 R) and (2R and 1 G) = 2*2*1 = 4.

 

and it may also be all the three faces are coloured either Red or Green, which can be doen in ( 3*2*1) * 2 = 12 ways

 

So the total number of ways is = 10 + 4 + 12 = 26.

 

Please correct me if I am wrong.

 

The future belongs to those who beleive in the beauty of their dreams.

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