Posted on: Sun, 2007-08-26 13:49
CL - Mock CAT 5
Use this thread only for Career Launcher Mock CAT 5 discussion
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Posted on: Sun, 2007-08-26 13:49
CL - Mock CAT 5
Use this thread only for Career Launcher Mock CAT 5 discussion __________________
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I found the test very tough and my performance is not close to what it was in last Sunday (in simCAT 1)
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My scores are sec1: 17
Sec2: 10.66
Sec3: 14.33
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Toatl 42
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My scores are pathetic to say the least
Total 24.3
I think the cutoff of MOCK 5 ‘ll be more than 45
I think it is an average paper. Similar to what CAT was till CAT06
I don’t think any one would have able to solve them
[Here AB is a two-digit number]
d. 66
can any one plz upload question paper.....so we can also solve it and discuss the issue........
please provide a lucid explanation to question no 60
For how many integer value of the constatnt "a", the two curves g(x) = x3 - x 2 + ax + 10 and
f(x) = x3 + ax3 + 3x + 11, never intersect each other ? [ x and a are real numbers]
a. 10
b. 9
c. 8
d. 7
The above problem can be solved like this:
For any two curves to intersect, there has to be a common solution to their equations. So for the two curve to intersect, such a common solution can be found out by equating them.
f(x) = g(x). Therefore, x3 + ax2 + 3x + 11 = x3 - x 2 + ax + 10.
or, (a+1)x2 + (3-a)x + 1 = 0.
Now for no solution, D<0. So, (3-a)2 < 4(a+1).
(9+a2-6a) - 4a - 4<0.
a2 - 10a + 5 <0.
a = (10 ± √80)/2 or, (5 ± 2√5). So the number of integral values is 9.
The future belongs to those who beleive in the beauty of their dreams.
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