help me solvin.....
Q===let M be the set of all the distinct factors of the number N=6^5*5^2*10, which are perfect squares.find the product of the elements contained in the set M
A-2^72*3^48*5^24 B-2^72*3^44*5^20 (PLEASE EXPLAIN ME THE PROCEDURE TO FIND THE PRODUCT PLEASE)
Q----there are two clocks .One of them gains 2min in 12 hrs and the another loses 2 min in 36 hrs .both are set right at 12 noon on tuesday .What will be the correct time when both of them show the same time for the next time?
a a2night b 1.30 am c 10.30 pm d 12 noon
So after 270 days on 12 noon both the clock ‘ll show the same time again with one day difference
thx for solvin yaar in the first question u have to first find the even multiples of M n the find there product...i just know this but dont know how to solve it
should not the required time difference be 12 hrs instead of 24. ie if we are also taking the am pm thingy into account.
But in the question it is written as 12 noon and the option had options in AM /PM . So I went for 24 hours
@. Searchin-life
your solution is not correct for the first question
hi guys,
for a perfect square the powers of prime factors mst be even....
N=6^5*5^2*10
N=2^6*3^5*5^3
so powers of 2 can be 2^0,2^2,2^4,2^6
so powers of 3 can be 3^0,3^2,3^4
so powers of 5 can be 5^0,5^2
so in total there will be 4*3*2 = 24 numbers....
Out of these every 6 numbers will have power 2^0,2^2,2^4,2^6
so total power of 2 will be 2^72
Out of these every 8 numbers will have power 3^0,3^2,3^4
total power of 3 will be 3^48
Out of these every 12 numbers will have power 5^0,5^2
total power of 5 will be 5^24
so total pdt will be 2^72*3^48*5^24
hiiii saheen...i cudnt under stand ur sol yaar....plz xplain it once more
see in a perfect square the powers of prime factors are always even....
e.g. 36 = 2^2 * 3^2
144= 2^4 * 3^2
so we find out wht can be the even powers of the factor....
2^0,2^2,2^4,2^6==>total numbers 4
3^0,3^2,3^4==>total numbers 3
5^0,5^2==>total numbers 2
so total perfect numbers generated will be 4*3*2 = 24
now in these 24 numbers 6 numbers will have power of 2 as 0
6 numbers will have power of 2 as 2
6 numbers will have power of 2 as 4
6 numbers will have power of 2 as 6.....
and frm hereon plz refer my earlier post...
i cant be clearer than this...
plz note my gmail id n we can chat abt any doubt if u have... shaheen.csc@gmail.com
regards,
shaheen
Is it this simple or I am making some mistake in understanding the question.