CAT4MBA

thx for solvin yaar in the first question u have to first find the even multiples of M n the find there product...i just know this but dont know how to solve it

should not the required time difference be 12 hrs instead of 24. ie if we are also taking the am pm thingy into account.

hi guys,

for a perfect square the powers of prime factors mst be even....
N=6^5*5^2*10
N=2^6*3^5*5^3

so powers of 2 can be 2^0,2^2,2^4,2^6
so powers of 3 can be 3^0,3^2,3^4
so powers of 5 can be 5^0,5^2

so in total there will be 4*3*2 = 24 numbers....

Out of these every 6 numbers will have power 2^0,2^2,2^4,2^6
so total power of 2 will be 2^72

Out of these every 8 numbers will have power 3^0,3^2,3^4
total power of 3 will be 3^48

Out of these every 12 numbers will have power 5^0,5^2
total power of 5 will be 5^24

so total pdt will be 2^72*3^48*5^24

hiiii saheen...i cudnt under stand ur sol yaar....plz xplain it once more

see in a perfect square the powers of prime factors are always even....
e.g. 36 = 2^2 * 3^2
144= 2^4 * 3^2

so we find out wht can be the even powers of the factor....
2^0,2^2,2^4,2^6==>total numbers 4
3^0,3^2,3^4==>total numbers 3
5^0,5^2==>total numbers 2

so total perfect numbers generated will be 4*3*2 = 24
now in these 24 numbers 6 numbers will have power of 2 as 0
6 numbers will have power of 2 as 2
6 numbers will have power of 2 as 4
6 numbers will have power of 2 as 6.....

and frm hereon plz refer my earlier post...
i cant be clearer than this...
plz note my gmail id n we can chat abt any doubt if u have... shaheen.csc@gmail.com

regards,
shaheen