hi
Sat, 2007-09-01 17:19
A no divided by 7 leaves 4 as rem..n when divided by 11 leaves 6 as rem..wt will b remain when it is div by 13...1000
Sat, 2007-09-01 17:21
#2
There are many smilar
Sat, 2007-09-01 17:27
#3
A no divided by 7 leaves 4
A no divided by 7 leaves 4 as rem..n when divided by 11 leaves 6 as rem..wt will b remain when it is div by 13...1000<no<2000.
A = 4 (mod 7)
= 6 (mod 11)
For A = 4 (mod 7), possible numbers are 11, 18, 25 . . ..
and the first number in the series divisible by 11 is 11
So N1 = 11
For A = 6 (mod 11), possible numbers are 17, 28, 39 . . . .
and the first number in the series divisible by 7 is 28
So N2 = 28
Thus A = N1 + N2 = 39
And all the numbers of the form 39 + 77K satsify the above two conditions.
A no divided by 7 leaves 4 as rem..n when divided by 11 leaves 6 as rem..wt will b remain when it is div by 13...1000<no<2000.
i found 39 as lowest.....here after how to proceed...the no is of nature 77a+39