THE SOLUTION OF ABOVE PROBLEM WILL BE........... 0.68.......OR 0.65 (APPROX )
THOUGH I DIDNT FOUND ANY PATTERN.... I JUST SOLVE THE GIVEN ANS WE KNOW IF BOTH NUMERATOR AND DENOMENTOR IS HAVING LARGE VALUE AND DIFFERENCE WILL BE LESS... THEN ITS SENSITIVITY WILL BE LESS AND IT WILL TENDS TO ONE SO............
THE SOLUTION OF ABOVE PROBLEM WILL BE........... 0.68.......OR 0.65 (APPROX )
THOUGH I DIDNT FOUND ANY PATTERN.... I JUST SOLVE THE GIVEN ANS WE KNOW IF BOTH NUMERATOR AND DENOMENTOR IS HAVING LARGE VALUE AND DIFFERENCE WILL BE LESS... THEN ITS SENSITIVITY WILL BE LESS AND IT WILL TENDS TO ONE SO............
WILL BE GLAD IF U LL SHOW ME OTHER WAY OUT
Ans is 2/3
Here T(n) = n^3-1/(n^3+1) where n varies from n=2 to infinty. Solving for product upto infinty will giveas 2/3.
can u plz explain how u gt that pdt to be 2/3 ??
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