SIM CAT 6
I think it was the toughest sim cat paper till now.
My scores are
DI : 42
Quant: 29
EU: 23
Total : 94
RC Sources:
Passage 1: Finding Clues in the Sky In 2004, the Olympics were once again held in Athens, and once again runners in Greece took the approximate route
The article was published on tims.com Passage I
Passage 2: The science of music Music seems to make no sense. It comes from nowhere and goes nowhere.
Taken from the article @ Passage II
Passage 3:what is about coffee – and coffeehouses – that makes it so agreeable to the bourgeoisie Passge 3 : No coffee
Get the complete article @ Passage III
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Thanks!!! Nisht
If you could have given these links before the exam 
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@ searchin –life
You have a point.
I think it should be none of the above
I feel the solution given is incomplete
The eqn is x2 + (2a +1) x + (a2 + 1) =0
For the above eqn to have a solution
(2a +1) 2 ≥ 4 (a2 + 1)
=> 4 a2 + 4a + 1 ≥ 4 a2 + 4
=> 4a + 1 ≥ 4
that means a >0
right , that means the answer should be none of the above. . .
or am I making any mistake
My scores are not that good. . don’t think will clear the cutoffs
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DI : 38
EU: 23
Quants : 18
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Total : 79 Horrible 
@ secondharsa
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read the question carefully
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it is written as the equation has positive roots
and what you are calculating is positive real roots.
No where its mentioned that the roots cant be complex positive roots.
Please revert back if you still have any doubt
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Hey Nishit !!!
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Thanks for the Clarification
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It was my mistake indeed . . .
Solution 24 is confusing
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Q24. A number, when written in base 16 notations, contains only three 0s and there 1s and no other digits. Find the maximum number of zeroes in the base 2 notation of that numbers.
ANS: 18
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Why only the highest and lowest numbers are considered
Why are not we considering some thing like 101100 / 110100. . .etc
How many 1’s are there in their binary representation . . .
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Please clarify 
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The solution should have mentioned that
Number of 1’s in base 16 = Number of 1’s in base 2
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So it’s about calculating maximum number of digits in base 2
And maximum number of 1’s in base 2 = Maximum number of digits in base 2 – 3
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For example consider 110100 = 165 + 164 + 162 = 1114368 = 220 + 216 + 28
= (100010000000100000000)2
It does not matter where you put the 1 in the base 16 numbers. . .there 'll be only three 1's in the equivalnt base 2 number.
As the maximum possible digits for given case is for (111000)16 = 165 + 164 + 163 is 21
Number of zeros = 21 - 3 = 18
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Any how my scores are DI : 24 Quant: 19 EU : 38 Total : 81
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Guys don’t you think the answer to Q21 should be
e. Cannot be determined
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because as per the question ?i=1n Xi = X1 * X2 * X3
and the question asks about xi – yi not about xi – yi
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Anyhow my scores are
DI : 38
Qunat : 34+
EU : 27
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Total : 99