a cl question

I need 2 know how u guys are approaching the following question

Your methods plz

The question was asked in a CL mock

A dealer marks up the cost price of an article by ‘p%’, and then gives a discount of ‘p%’ on the marked price. Now the price of the article is Rs. 21 less than the cost price of the article. He again marks up the decreased price by ‘p%’ and then gives a discount of ‘p%’ . if the price of article now is Rs. 2058,then find the value of p?
 a. 8

b. 9

c. 10

d. 12

We can solve this prob by

We can solve this prob by trial and error

it takes less time than conventional method

Since in the first case the CP has been rised by   p % and then

discounted by  p% there will always be loss of p2/100  %

Since the given diff between CP  and the discounted prices is  21

and the final cost of article  is  2058  the ans should be around  10%

lets take  p  =  8% then the loss is only 0.64 % which makes the initial CP as 3250,

which is far from 2058 ( keep in mind that the loss is only 0.64%).

Similarly check with 9% and then with 10%

the ans is (C) 10%

It would be wise to check with 10% first.

Pls post whether the ans is correct or not

thank u

shahid

 

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Thanks shabash_23

Thanks shabash_23

Pls post if u have any other

Pls post if u have any other alternative method

to find the solution.

thank u

shahid

__________________

n/a

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