1] A person has a number of one rupee coins which he tries to arrange in the form of a square.On the first attempt he has rs 116 over and when he increases the scale of the square by 3,he wants rs 25 more to complete the square.How many rupees does he have.? 2] At a fun fair,each mother had brought 2 children along.At the end of the day,it was found that 36 mothers had lost one or both of their children and 62 children had lost their mothers .How many mothers had lost only one of their children and how many mothers had lost both of their children? __________________
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I guess its quite simple
Am I rgt?
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Hi Nishit i got same answer too.....
1st approach,
Suppose the no. of mothrs who had lost 1 child r x....
So, the no. of mothrs who had lost 2 children r 36-x...
x + (36 - x) X 2 = 62
=> x =10
For 1 it's 10
For 2 it's 26...
ALTERNATIVELY
At the end of the day 36 x 2 -62 = 10 childrn wud cm back.....
As evry mothr had lost at last one child.So,10 childrn had one mothr each.
We can conclude dt the no. of the mothrs contain 1 child shud b 10 & for 2 shud b 36-10=26..
GIVE YOUR BEST TO THE WORLD..
AND THE BEST WILL COME BACK TO YOU......
Regards,
Dipanjan....
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Well the answer to the second question is exactly right, where as the answer to the first question is 600 coins, would anybody like to give a try.
Thanks
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The earlier answer given (incognito means by an unknown person) is wrong. .what he has considered(I guess) is the number of coins required along the side.
Number of coins required to make a square is always a square number i.e 4, 9, 16, 25. . etc . .in the below picture I have tried to show how to arrange 4, 9, 16 coins
Let x2 be the number of coins that the person has . . when he ‘ll try to increase the square by three, the number of coins required ‘ll be (x+3)2
As per the question when he puts x2 number of coins to form the square, he is left with 116 coins and when he (x + 3)2 number of coins, he is short of 25
So
(x + 3) 2- x 2 = 116 + 25
=> 6x + 9 = 141
=> x = 22
He has 484 + 116 = 600 coins
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This is really a wonderful explaination given by you Nishit, thanks a lot , this really clears every doubt.
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