Hello all, Can someone give me a solution for this problem? There are 100 children numbered 1 to 100. There are also boxes numbered 1 to 100. Each box contains 1000 toffees. The first child takes 1 toffee from each box numbered 1,2,3,....100. The second child takes 2 toffees from each box numbered 2,4,6,....100, the third child takes 3 toffees from boxes numbered 3,6,9,...99 and so on till the 100th child. Which among the following is / are false? 1. The box left with minimum number of toffees is box numbered 64. (A) 1 & 2 Thanks in advance. |
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All are true ans D
Condition 3 : true box number 1 and 2
Condition 2 : true from box number 26 – 50
Condition 1 : sum of the divisors is highest for 64 between number 1 to 100.
Or you can try by simply calculating it for few boxes like
Stupid example
For 1st box : 1
For 2ndt box : 1 + 2 = 3;
For 3rd box : 1 +3 =4 ;
For 4th box : 1 + 2 + 4= 8;
For 5th box : 1 + 5 =6;
For 6th box : 1 + 3 + 6 =10;
For 7th box : 1 + 7 = 8;
For 8th box : 1 + 2 + 4 +6 + 8 =21;
For 9th box : 1 + 3 +9 =13;
For 10th box : 1 + 10 =11;
For 1 – 5 its 4, for 1 – 10 its 8
And its 16 for 1-20
24 fo 1-30
Because these numbers got the highest number of divisors and their sum is always more
But in the key provided it is given that only statement 1 is true.
Let's us check if we had missed anything.
Thank you.
condition 3 is satisifed only by box 1 not 2
so only 1 and 2 are correct
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