A semi-circle is drawn...
A semi-circle is drawn with AB as its diameter.
From C, a point on AB, a line perpendicular to AB is drawn meeting the circumference of the semi-circle at D.
Given that AC = 2 cm and CD = 6 cm,
the area of the semi-circle (in sq. cm) will be:
CD and o, the center of circle forms right angled triangle
with side lengths 6, r, r-2, where r is the center of circle
we get r=10 and area of semicircle as 50pi
CD and o, the center of circle forms right angled triangle
with side lengths 6, r, r-2, where r is the center of circle
we get r=10 and area of semicircle as 50pi
we form right angle triangle wtih sides CD and center of cirlce
side lenghts 6, r, r-2
r=10
area = 50pi
let the radius be r and center be at o,
then,
in triangle ocd oc= r-2; od= r & cd=6
6^2 + (r-2)^2=r^2
r=8
so, pi r^2= 64 pi
can not be determined