4^4444 + 3^333 is divided by 7
4^4444 + 3^333 is divided by 7
n/a
1+6=7, so remainder is 0
The value of n is not the same one is 1111 and next is 111 and so how come its remainder will be zero
4^4444 = 2^8888 and 2^3 / 7 gives a remainder = 1
8888 = 3*2062 + remainder 2
hence 4^4444 divided by 7 gives a remainder = 2^2 = 4
3^3 = 27 when divided by 7 gives a remainder = 6 or -1
and (-1)^111 = -1
hence remainder = +4 - 1 = 3
abe sale galat multiply krna nhi ata...CAT nikalne chala hai
4^4444 + 3^333
------------------------- = 4^(3(1448) + 3^(6(56)) * 3^3
7 -------------------------------------------- = (1+6)/7 =7/7.
7
therefore remainder is 0 zero.

ans-3